-16x^2+256x+10=0

Solution for -16x^2+256x+10=0 equation:

-16x^2+256x+10=0

a = -16; b = 256; c = +10;
Δ = b2-4ac
Δ = 2562-4·(-16)·10
Δ = 66176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{66176}=\sqrt{64*1034}=\sqrt{64}*\sqrt{1034}=8\sqrt{1034}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(256)-8\sqrt{1034}}{2*-16}=\frac{-256-8\sqrt{1034}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(256)+8\sqrt{1034}}{2*-16}=\frac{-256+8\sqrt{1034}}{-32}
$